X=16t^2+5t+5

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Solution for X=16t^2+5t+5 equation: 



X=16X^2+5X+5

We move all terms to the left:

X-(16X^2+5X+5)=0

We get rid of parentheses

-16X^2+X-5X-5=0

We add all the numbers together, and all the variables

-16X^2-4X-5=0

a = -16; b = -4; c = -5;
Δ = b2-4ac
Δ = -42-4·(-16)·(-5)
Δ = -304
Delta is less than zero, so there is no solution for the equation

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